andmad


 * maan56 Click for Circles

Lesson 1** 1) Explore ratios of surface area to volume. 2) Develop te concepts of (2)maximizing volume and minimizing surface area.

1) Define and use formula for finding the (2)surface area of a right prism. 2) Define and use a formula fo finding the volume of a right prism. 3) use calvaileri's principal to develope a fromula for the volume of a right oblique prism.
 * Lesson 2**

1) Define and use a formula for the (2)surface area of a regular pyramid. 2) Define and use a formula for the (2)volume of a pyramid. 1) Define and use a formula for the surface area of a right cylinder. 2) Define and use a formula for the volume of a cylinder.
 * Lesson 3**
 * Lesson 4**

1) Define and use the formula for the surface area of a cone. 2) Define and use the formula for the volume of a cone.
 * Lesson 5**

1) Define and use the formula for the surface area of a sphere. 2) Define and use the formula for the volume of a sphere.
 * Lesson 6**

1. Volume of triangular prism there is an aquarium that has the dimensions of 50ft X40ft X20ft. what is the volume of the aquarium? The volume is V =Bh lwh= (50)(40)(20) = 40000ft cubed 2. surface area of triangular prism there is a net that has the measerments: h =40, s2 31, s1= 27, and s3 20 the lateral area is L = 40(78) 3120 the area of each base is B = 1/2(2)(31) 31 Perimeter of each base is P = 27 + 31 + 20 78 surface area is S = 3120 + 2(31) 3182

3. volume of a pyramid The base edge of a pyridim is about 388 feet and a height of about 240.5 feet. V = (1/3)(388^2)(240.5) 12068610.67 cubic feet

4. surface area of a pyrimid a square pyramid whose slant height is 6 feet and a base edge length of 3. S = 4(.5(6)(3)) + 6^2 72 square feet

5. volume of a cylinder there is a cylinder tank that has a lenght of 15.5 feet an outer diameter of 4 feet. V = π2^2(15.5) 194.7788 cubic feet

6. surface area of a cylinder A circle has a diameter of 20 cm making a radius of 10 cm S =2π(10)(20) + 2π10^2= 1884.96 spuare cm

7. volume of a cone There is a hill of dirt that has a radius of 10 feet and a hight of 4 feet V =(1/3)π10^2(4)= 487.88 cubic feet

8. surface area of a cone hill of dirt that has a radius of 10 feet and a hight of 4 feet S =π10(2.4) + π10^2= 389.56 square feet

9. volume of a sphere the sphere has a radius of 5 cm V =(4/3)π5^3= 523.60 cubic cm

10. surface area of a sphere