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**CHAPTER 7.1**
1. Surface Area and Volume Formula: The surface area S, and the volume V, of a right rectangular prism with length l, width w, and height h are: S=2lw+2wh+2lh V=lwh The surface area S, and volume V, of a cube with side s are: S=6s2 V=s3

Chapter 7.2
1 surface area of right prism [|right prism] The surface area, S, of a right prism with lateral area L, base area B, perimiter p, and height h is S L + 2B or S + hp + 2Br **ALTITUDE-** is a segment that has endpoints in the planes containing the bases and that is perpendicular to both planes. **HEIGHT-** Is the length of an altitude

Chapter 7.3 area of a regular pyramid
1. Define and use a formula for the surface area of a regular pyramid. 2. Define and use a formula for the volume of a pyramid. A polyhedron consisting of a base which is a polygon,and three or more lateral faces. vertex of a pyramid, lateral faces of thrangles that share the same, single vertex base edge, each lateral face has one edge in common with the base regular pyramid, a pyramid with base that is a regular polygon and lateral faes are congruent isoceles triangels slant height, length of an altitude of a lateral face of a regualar pyramid!!!!

Chapter 7.4 surface area and volume of cylinders
[|cylinder] 1. Use a formula for the surface area of a right cylinder 2.Use a formula for the volume of a cylinder. Keywords a solid that has a circular region and its translater image on a parallel plane with a lateral surface connection the circles //Axis,// segment joining the centers of the two bases //Formulas Surface area for a right cylinder, s//l+2b or s=2(pi)rh+w(pi)r^2 Volume of a cylinder, v=bh or v=(pi)r^2h **Example**, a cylinder, r=12 height is 7, find the SA. 2(pi)12*7

Chapter 7.5 Surface area and volume of cones
[|cone] 1.Define and use the formula for the surface area of a cone 2. define and use the formula for the volune of a cone = = Keyword Cone, thre dimensional shape figure that has a circular base and a curved lateral surface Surface area of a right conesl+b or s=(pi)rl +(p)r^2 Volume of a cone, v=1/3bh or v=1/3(pi)r^2h= = =
 * Example** surface area, lets say you have a lateral side area of 50 and a base of 50 all that would need to be done is add them,(100^2) however it often isnt that easy. Usally you'll have to find the lateral area and the base first

Chapter 7.6 surface area and volume of spheres
[|sphere] 1. Define and use the formula for the surface area of a sphere 2. Define and use the formula for the volume of a sphereA spere is the set of all points in the space that are the same distance, r, from a given point known as the center of the sphere. //Surface area of a sphere, s = 4(pi)r^2 Volume of a sphere, v=4/3(pi)r^3// first take the radius, it should be given, and plug it into the formula 4(pi)r^2 so lets say the radius was 2 it would be 4(pi)2^1 which turns out to be approx.50.27
 * Formulas**
 * Example**

Chapter 7.7 three dimesional symetry [|three dimensional symmetry] 1. define various transformations in three demisional space 2. solve problems by using transformations in three demisional space

1. Volume of a triangular prism - S= hp+2B if the height is 5 and the base is 20 and the peimiter is 15 then S=(5)(15)+2(20) = 1540 2. Surface Area of a triangular prism - V=Bh so if your base was 5 and your height was 4 V=(5)(4) wich = 20 3. Volume of a pyramid - V=1/3Bh so if the base is 9 and the height is 3, V=1/3(9)(3) = 9 4. Surface Area of a pyramid - SA=1/2lp+B so the slant height is 5, width and length are 10 and the Base is 4 so SA=1/2(5)(15)+4 = 41.5 5. Volume of a cylinder - V=πr^2h the radius is 20 and the height is 5 V=π(200)(5) = 1000π 6. Surface Area of a cylinder - SA=2πrh+2πr^2 if the radius is 10 and the height is 5 SA=2π(10)(5)+2π100 = 300π 7. Volume of a cone - V=1/3Bh the base is 30π and the height is 4 V=1/3(30π)(4) = 40π 8. Surface Area of a cone - SA=πrl+πr^2 if the radius is 4 and the slant height is 2 SA=π(4)(2) + π(16) = 24π 9. Volume of a sphere - v=4/3(pi)r^3 if the diameter is 18 V=4/3π(9)^3 = 643238.64631π 10. Surface area of a sphere - SA=4πr^2 if the radius is 9 SA=4π(81)= 324π = =