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//**__To find a great math [|song]__**//
__Geometry__ [|song] If you dont understand a problem go to [|Doctor math]. Got to the bottem and tpe in what you need. =LESSON 7.1 Surface Area and Volume Formula:=

IF YOU WANT A PLACE TO GET GREAT GEOMETRYGAMES? [|GAME] IF YOU DONT SEE A WORD YOUR LOOKING FOR GO [|HERE] The surface area S, and the volume V, of a right rectangular prism with length l, width w, and height h are: S=2lw+2wh+2lh V=lwh The surface area S, and volume V, of a cube with side s are: S=6s2

[|Right Prism] If you are having problems you can use blocks or rubix cubes can too. It can really help you.

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Here is a problem!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
If the length of a rectangular prism is 4. The hight is 6 and the with is 2. What is the surface area and volume. Fist is surface area. S= 2(4)*(2)+2(2)*(6)

S=16+48+24 That equals 88 Now here is volume. V=LWH V=4*2*6= 48.

=Lesson 7.2 Surface Area and Volume of Prisms=

Surface Area of a Right Prism
The surface area S, of a right prism with lateral area L, base area B,perimeter p, and h is S=L+2B or S=hp+ 2b.

Cavalieri's Principle
If two solids have equal hights and the cross selections formed by evry plane parallel to the bases of both solids have equal aareas, then the two soilds have equal volumes.

Volume of a rectangular prism
The volume, v, of s prism with height h and base area B is V=Bh.

Here is a problem.
what is the surface area of this. l=5 w=7 h=2 V=bh =L * W * H= 5 * 7 * 2= 70 A pentagon shape.

=Lesson 7.3 Surface Area and Volume of Pyramids=

Surface Area of a Regular Pyrmaid
The surface area, S, of a regular pyramid with lateral area L, base area B, perimiter of the base P, and slant hight I is S= L + B or S= 1/2 IP+B.

Volume of a pyramid
The volume, V, of a pyramid with hight h and base area B is V=1/3Bh.

Here is a problem!!!!!!!!!!!!
If the pyrmid has a length of 2 a height of 4 and with of 6. V=1/3+2*4*6 V=16 Triangular Pyramid Rectangular Pyramids Pentagonal pyramaid Hexagonal Pyramids

A real life example of using these math problems is for buildings for example. Look at the top of the roof. You can figure out surface area, volume[|.]

Another place that you can use these math formulas is in bridges. You can find missing lenghts for a bridge. As you should know that the strongist shape is a triangle as you look below you can see them all over in bridges.



=Lesson 7.4 surface Area and Volume of Cylinders=

Surface Area of a Right Cylinder
The surface area, S, of s right cylinder with lateral area L, base area B, radius r, and hight h is S=L=2B or S= L +2B or S= 2pi,radius squared,h.

Volume of a cylinder
The volume, V, of a cylinder with a radius r, hight h, and base area B is V=Bh.

=Lesson 7.5 Surface Area and Volume of Cones=

Surface area of a right cone
The surface area, s, of a right cone with lateral area L, base of area B, radius r, and slant hight l is S= L+B.

Volume of a cone
The volume, V, of a cone with a radius r, height h, and B is V= 1/3Bh. [|Cone]

=Lesson 7.6 Surface Area and Volume of Spheres=

Volume of a sphere
The volume, V, of a sphere with a radius r is V=4/3*3.14r3.

Surface Area of a sphere
The surface area, S, of a sphere with radius r is S=4*3.14*r2.

A real life example of using these formulas for this lesson is for softballs and baseballs or a majic eight ball. With those formulas you can figure how much suface area and the volume it takes to cover it. [|Eightball] [|baseball] Here is a [|great quiz]. NOTE: If you are having a problems see your work to here and it will show your [|shape]. If you want to play a math game that tells you the answers to the [|questions of shapes]. If you are a person that cant remember formulas you should go here are see if it [|helps]. If you need math help in general go here for [|help].

1. Volume of a triangular prism
V= Bh, v=(7)(5) V= 35units^3

3. volume of a priamid
V= 1/3Bh, base area= 1/2(4)(3) B=6 H+5 V=1/3(6)(8)=16units^3

4.Surface area of a pyramid
SA=1/2lp+B 1/2(6)(16)+24=72units^2

5. Volume of a cylinder
diameter 8 hieght 10 V=pi*r^2h pi(8)^2(10) 640pi = 2009.6u^3

6. Surface area of a cylinder
diameter 6 height 8 SA= 2pi(3)(8)+2pi(3)^2 48pi+18pi

7. Volume of a cone
Radius 7 height 10 V=1/3pi*r^2=1/3pi(7)^216.17Pi or 50.77units^3

8. Surface area of a cone
slant height 15 radius 5 SA= pi*r^2 pi(5)(15)+pi(5)^2 75pi+ 25pi 100pi or 314units^2

9. Volume of a sphere
radius=9 V=4/3pi*r^3+4/3pi(9)^3 36pior 113.04units^3

10.Surface area of a sphere
radius=22 SA=4pi*r^2=4pi(22^2 1936pi or 607.04units^2